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Free Online Test
image Online Test 1 (Percentage)

Number of questions : 20  |  Time : 30 minutes

image Online Test 2 (Percentage)

Number of questions : 20  |  Time : 30 minutes



Important Notes and Previous Year Questions :

Percentage:

Here we provided formulae and hints for Percentage category.  Requesting you to read the below points before taking online test.

Normally Percentage is defined as the fraction having denominator is 100 and numerator of the fraction is called rate of percent.

Percentage is denoted by ‘%’ symbol.

X % of Y => (X / 100) * Y

If X is a% more than Y, then Y is less than X by => {[A / (100 + A)] * 100} %

If X is a% less than Y, then Y is more than X by => {[A / (100 - A)] * 100} %

 

Previous year solved Questions:

1. 89% of ? + 365 = 1075.22

A) 798                   B) 897                    C) 898                    D) 752                   E) None of these

Ans: A

Solution: 89% of X = 1075.22 – 365 = 710.22

                => (89 / 100) * X = 710.22

                =>X =(710.22 * 100) / 89 = 798

 

2. The difference between 78% of a number and 59% of the same number is 323. What is 62% of that number?

A) 1054                 B) 1178                 C) 1037                 D) 1159                 E) None of these

Ans: A

Solution: According to given data,

                => (78 – 59) % of X = 323

                => (19 * X) / 100 = 323

                => X = 1700

But we need to calculate 62% 1700 = 1054

 

3. Kiran spends 25% of his monthly income on household expenses. His annual income is Rs. 4.32 lac. What is the total amount that Kiran spends on household expenses in 8 months together?

A) Rs. 74000        B) Rs. 71000        C) Rs. 73000        D) Rs. 72000        E) None of these

Ans: D

Solution: Annual Household expenses = {25% of 4.32 * 10 power 5}

                => (25 * 4.32 * 10 power 3)

Therefore household expenses for 8 months = {(25 * 4.32) / 12 * 8 * 10 power 3} = 72000/-

 

4. In an examination, it is required to get 296 marks out of aggregate marks to pass. A student gets 222 marks and is declared failed by 10% marks. What are maximum aggregate marks a student can get?

A) 830                   B) 810                    C) 780                    D) 740                   E) None of these

Ans: D

Solution: Given data, assume maximum aggregate marks = X say

                So, 10% of X = 296 – 222

                =>  10% of X = 74

                => X = 74 * 10 = 740