Simplification online test - Aptitude
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Simplification formula
1. BODMAS rule
The BODMAS rule refers to the rule that is followed to solve mathematical expressions. The BODMAS stands for B - Brackets, O - Order of powers, D - Division, M - Multiplication, A - Addition, and S - Subtraction
2 .Modulus of a Real Number
Thus, |5| = 5 and |-5| = -(-5) = 5
3. Virnaculum (or Bar)
When an expression contains Virnaculum, before applying the 'BODMAS' rule, we simplify the expression under the Virnaculum.
Example - $\ov\text x$
Solved Simplification Questions for upcoming Exams
Simplification using BODMAS
Some Questions With Solutions:-
Ans - Let '*' be H
$[(H)/21 × (H)/189]$ = 1
$(H)^2$ = 21 × 189
H = $√{21 × 189}$ = 63
= ${{75/90} + {7.5}}/{{{2}318/990} - 98/990} = {{75/90} + {7.5}}/{{2}220/990}$
= ${7.5}/{90 × {7.5}} × 990/2200 = 1/20 = 0.05$
${5/3} ÷ {2/7} × \text"*"/7 = {5/4} × 2/3 × 6$
${5/3} ÷ {2/7} × \text"*"/7 = {5 × 2 × 6}/{4 × 3}$
* = ${5 × 2 × 6 × 3 × 2 × 7}/{5 × 7 × 4 × 3} = 6$
−∣−48∣
=−(48)=−48
Simplification based on square & square root
= ${√{16 × 5} - √{16 × 7}}/{√{9 × 5} - √{9 × 7}}$
= ${4√{5} - 4√{7}}/{3√{5} - 3√{7}} = {4(√{5} - √{7})}/{3(√{5} - √{7})$
= $4/3 = 1{1}/3$
= ${(75.8 - 55.8)(75.8 + 55.8)}/20$
= ${20 × 131.6}/20$ = 131.6
= $√{{(10 × 0.61)^2 + (10 × 6.11)^2 + (10 × 61.11)^2}/{(0.61)^2 + (6.11)^2 + (61.11)^2}}$
=$√{100}$ = 10
Simplification based on cube & cube root
= $7/4 = 1{3}/4$
Solution-
$√^3{{72.9}/{0.4096}} = √^3{{729000}/{4096}}$
= $√^3{(90)^3/(16)^3} = 90/16 = 45/8 = 5.625$
Simplification with continued fraction
Solution-
$2/{2 + 2/{3 + 2 /{3 + {2/3}}}× {0.39}}$= $2/{2 + 2/{3 + 2/{11/3}}× {0.39}}$
= $2/{2 + 2/{3 + {6/11}}× {0.39}}$
= $2/{2 + 2/{{33+6}/11}× {0.39}}$
= $2/{2 + {{11×2}/39} × {0.39}}$
= $2/{2 + {{11×2}/39} × {39/100}}$
= $2/{2+{11/50}} = 2/{{100+11}/50} = 100/111$
Solution-
First part = ${30/7 - 1/2}/{7/2 + 8/7}$= ${{60 - 7}/14}/{{49+16}/14} = {53/14} × 14/65 = 53/65$
Second part = $1/{2+1/{2+{1/{{25 - 1}/5}}}}$
= $1/{2+1/{2+{5/24}}} = 1/{2+{1/{{48+5}/24}}}$
= $1/{2+{24/53}} = 1/{{106+24}/53} = 53/130$
Expression = ${53/65} ÷ {53/130} = 53/65 × 130/53 = 2$
Simplification Questions and Practice Problems
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Simplification:
Read the following points carefully.
TYPES OF NUMERALS:
1). Natural Numbers: These are counting numbers. For Ex. 1,2,3,4,5……
a) Natural numbers are denoted by ‘N’.
b) All natural numbers are positive only.
c) 0 is not a natural number. The smallest natural number is ‘1’
2). Whole Numbers: Whole numbers having ‘0’ and natural numbers. Ex.0, 1, 2, 3, 4…….
a) Denoted by ‘W’
3) Integers: Negative numbers and whole numbers forms integers. Ex. -3, -2, -1, 0, 1, 2, 3….
a) Denoted by ‘I’
b) ‘0’ number is neither positive nor negative.
4) Even and Odd Numbers: The counting numbers which are divisible by 2 then those numbers called Even numbers otherwise Odd numbers.
a) Ex. For even numbers: 2, 4, 6, 8,10 ….
b) Ex. For odd numbers: 1, 3, 5, 7,9 ….
5) Prime Numbers: These numbers having only two factors ‘1’ and itself.
Ex. 2, 3, 5, 7, 11, 13 …. 2 is the even number which is prime and prime number is always greater than 1.
6) Rational and Irrational Numbers: Rational numbers are represented in the form of (a/b) where b is not equal to ‘0’, a and b are integers. Ex. (1/2), (2/5), (3/8)…
Irrational numbers cannot be represent in the form of (a/b). Ex. Square roof of 2
7) Composite Numbers: These numbers are not prime numbers and having at least one factor other than ‘1’ and itself.For Ex. 4, 8, 12…
Divisibility Rules:
1. Divisibility by 2: If the number is having either ‘0’ or even number as a last digit then that number is divisible by 2.
Example: 24, 40, 68, 122
2. Divisibility by 3: When sum of the digits of a number is divisible by 3, then the number is divisible by 3.
Example: 159 1 + 5 + 9 = 15 15 is divisible by 3.
3. Divisibility by 4: If the last two digits of a number is divisible by 4, then that number is divisible by 4.
Example: 124 24 is divisible by 4
If the number is having two or more zeroes at the end then also its divisible by 4.
Example: 1200 it’s having two zeroes at the end so its divisible by 4.
4. Divisibility by 5: If the number is having ‘0’ or ‘5’ at the end then it’s divisible by 5.
Example: 150, 205, 300
5. Divisibility by 6: If the number is divisible by 2 and 3then that number should divisible 6.
Example: 36, 54, 60
6. Divisibility by 7: when the difference between twice the digit at last place and the number formed by other digits is either ‘0’ or multiple of ‘7’.
Example: 147 14-(2*7) = 0 144 is divisible by 7
7. Divisibility by 8: If the number made by last three digits is divisible by 8, the number is divisible by 8.
Example: 24032 032 is divisible 8
8. Divisibility by 9: It’s similar to divisible by 3 rule. When sum of the all the digits of a number is divisible by 9, then the number is divisible by 9.
Example: 4374 4 + 3 + 7 + 4 = 18 18 is divisible by 9
9. Divisibility by 10: If the number is end with ‘0’ then it’s divisible by 10.
Example: 50, 110, 2000
10. Divisibility by 11: If the sum of digits at odd and even places are equal or differ by a number which is divisible by 11 then the number is divisible by 11.
Example: 216282 sum at even places(2+6+8) = 16; sum at odd places (1+2+2) = 5
Difference: (16-5) = 11. So 216282 is divisible by 11.