The method in which you can find the value of a unit and the a required number of units.

Let's assume you go to the market to purchase 6 Mangoes. The shopkeeper tells you that he is selling 10 Mangoes for Rs 100. In this case, the Units are Mangoes and the Value is the cost of the Mangoes. While solving a problem using the unitary method, it is important to identify the units and values.

For simplification, it is always suggested to express the calculated quantities on the right-hand side and the known quantities on the left-hand side. In the given problem, we are informed about the amount of Mangoes, but the value of Mangoes is unknown. It is necessary to keep in mind that the concept of ratio and proportion are commonly applied to this problems that are used this method.

The best Strategy to enhance your knowledge in Unitary Method sharpen your skills by utilizing the Free Online Test platform, where you can acquire various practice questions and their solutions.

**Question-1) **

**A Bus travelling at a speed of 140 kmph covers 420 km. How much time will it take to cover 280 km?**

**Answer: **

First, we need to find the time required to cover 420 km.

Speed = $\text"Distance"/\text"Time"$

140 = $420/T$

T = 3 hours

Applying the unitary method,

420 km = 3 hours

1 km = $3/420$ hour

280 km = $(3/420) × 280$ = 2 hours

**Question-2)**

**If 6 identical machines can produce a total of 270 bottles per minute, what is the total number of bottles that 10 such machines could produce in 4 minutes, assuming they run at the same constant rate?**

**Anwer:**

From question,

6 ${\text"machines can produce"} = 270$ bottles in 1 minute

then,$ 1 {\text"machine can produce"} = {270} / 6$ bottles in 1 minute

So,10 ${\text"machines can produce"} = {270 × 10 }/ 6$ bottles in 1 minute

Then, 10${\text"machines can produce"} = {270 × 10 × 4} / 6$ bottles in 4 minute

So, 10 ${\text"machines can produce"} = 45 × 10 × 4$ bottles in 4 minute

then,10 ${\text"machines can produce"}= 1800$ bottles in 4 minute

**Question-3) **

**P finishes his work in 15 days while Q takes 10 days. How many days will the same work be done if they work together?**

**Answer:**

If P takes 15 days to finish his work then,

P’s One day of work = $1/15$

Similarly, Q’s One day of work = $1/10$

Now, total work is done by P and Q in 1 day = $1/15 + 1/10$

Taking LCM(15, 10), we have,

One day’s work of P and Q = ${(2+3)}/30$

One day’s work of (P + Q) = $1/6$

Thus, P and Q can finish the work in 6 days if they work together.

**Question-4)**

**If a worker makes a toy every 2 hours, how many toys will he make if he works for 80 hours?**

**Answer:**

According to question,

worker makes 1 toy in every 2 hours,

then in 1 hour, worker makes $1/2 $ toy

In, 80 hour worker can makes $(1/2 )$ × (80 hours) = 40 toys

then, the worker will make 40 toys in 80 hours

**Question-5)**

**If the price of $1/4$ kg is Rs. 0.60, then find the cost of 200 grams?**

**Answer:**

We know,

1 kg = 1000 grams

⇒$1/4$ kg = 1000 × $1/4$ = 250 g

from question, the price of 250 g = 60 paise

then, the price of 200 g = $60 / {250} × 200 $

= 48 paise

Online Test - 1 (Unitary Method) TAKE TEST
Number of questions : 20 | Time : 30 minutes |

Online Test - 2 (Unitary Method) TAKE TEST
Number of questions : 20 | Time : 30 minutes |