# Time and Distance MCQ - Time and Distance Solved Questions

Welcome to freeonlinetest online web portal, In this section you will learn about Time, Speed and distance MCQ, shortcut tips, formulas, solved examples, problems on time spped and distance, quantitative aptitude MCQ Questions, quiz, solutions, pdf downloads.

Nowadays competitive exams became very tough for candidates who are preparing competitive exams like SSC CGL, SSC CHSL, SSC MTS, Group D, Police Jobs, Banking, etc, though all most of the candidates have aptitude-solving skills but they don't know how to solve it in less time or you can say they don't know time management, here you will how to solve the time and Distance aptitude MCQ questions with less time by using some simple tricks.

## Shortcut Tricks and Formulas on Time Speed & Distance

Trick-1

If a man travels different distances $d_1,d_2,d_3$,... and so on in different time $t_1,t_2,t_3$ respectively then,

Average speed = $\text"total travelled distance"/\text"total time taken in travelling distance"$

= ${d_1 + d_2 + d_3 +...}/{t_1 + t_2 + t_3 +...}$

Trick-2

If a bus travels from A to B with the speed x km/h and returns from B to A with the speed y km/h,then the average speed will be $({2xy}/{x + y})$

Trick-3

If a man travels different distances $d_1,d_2,d_3$, and so on with different speeds $s_1,s_2,s_3$, respectively then,

Average speed = $({d_1 + d_2 + d_3 + ...})/{d_1/S_1 + d_2/S_2 + d_3/S_3 + ...}$

Trick-4

If a man travels at the speed of $s_1$, he reaches his destination $t_1$ late while he reaches $t_2$ before when he travels at $s_2$ speed, then the distance between the two places is

D = ${(S_1 × S_2)(t_1 + t_2)}/{S_2 - S_1}$

## Some Problems on Time, Speed & Distance MCQ

Question-1)

An athlete runs 200 metres race in 24 seconds. His speed (in km/ hr) is

A) 18 km/hr

B) 30 km/hr

C) 45 km/hr

D) 56 km/hr

Ans- B

Explanation:

Speed = $\text"Distance"/\text"Time"$

= $200/24$ m/s

$200/24$ m/s = $200/24 × 18/5$

= 30 km/h [Since, x m/s = $18/5$ x km/h]

Question-2)

A boy goes to his school from his house at a speed of 3 km/hr and returns at a speed of 2 km/ hr. If he takes 5 hours in going and coming, the distance between his house and school is

A) 1 km

B) 3 km

C) 5 km

D) 6 km

Ans- D

Explanation:

Here, x = 3, y = 2

Average Speed = ${2 × x × y}/{x + y}$

= ${2 × 3 × 2}/{3 + 2} = 12/5$ km/hr

Total distance = $12/5 × 5$ = 12km

Required distance = $12/2$ = 6 km

Question-3)

A boy runs 20 km in 2.5 hours. How long will he take to run 32 km at double the previous speed ?

A) 1 hrs

B) 3 hrs

C) 2 hrs

D) 6 hrs

Ans- C

Explanation:

The boy covers 20 km in 2.5 hours.

Speed = $20/{2.5}$ = 8 km/hr.

New speed = 16 km/hr

Time = $32/16$ = 2 hours.

Question-4)

A man travelled a certain distance by train at the rate of 25 kmph. and walked back at the rate of 4 kmph. If the whole journey took 5 hours 48 minutes, the distance was

A) 15 km

B) 12 km

C) 20 km

D) 18 km

Ans- C

Explanation:

If a bus travels from A to B with the speed x km/h and returns from B to A with the speed y km/h,then the average speed will be $({2xy}/{x + y})$

Here, x = 25, y = 4

Average speed = ${2xy}/{x + y}$

= ${2 × 25 × 4}/{25 + 4} = 200/29$

Total Distance = $200/29 × 5{4}/5$

= $200/29 × 29/5$ = 40 km

Required distance = 20 km

### Test instructions :

• Total number of questions : 20
• Each question carries 1 mark
• Negative marks of Each Questions: 0.25
• Skiping questions No marks will deduct.
• Time allotted : 30 minutes